1. From the Interval (-2,0)U(0,2), f(x) is increasing, f ' (x) is the slope of f(x), and the in that interval, the points are positive, positive slope = increasing
From (-infinity, -2) U (2, infinity), f(x) is decreasing, because the slope is negative, points on f ' (x) graph are negative in that interval
2.At x= -2, f ' (x) changes from negative to positive, making it a local minimum.
at x = 2, f ' (x) changes from positive to negative, making it a local maximum
3. In the interval (-infinity, -1.5) U (0,1.5) , the slope of the f ' (x) graph is positive, f ''(x) > 0 is concave up
in the interval (-1.5 , 0) U (1.5 , infinity), the slope of f '(x) is decreasing, f ''(x) < 0 is concave down
Tuesday, February 16, 2010
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1. Yup!
ReplyDelete2. Great!
3. Perfect.
4. This f' graph looks like it could be a cuartic, or a 4th degree power function. Therefore the antiderivative must be a 5th degree function.